Question

giúp mik với

Answer 1

\(=\int\limits^1_{-1}\sqrt{\left(e^x-1\right)^2}dx=\int\limits^1_{-1}\left|e^x-1\right|dx=\int\limits^0_{-1}\left(1-e^x\right)dx+\int\limits^1_0\left(e^x-1\right)dx\)

\(=\left(x-e^x\right)|^0_{-1}+\left(e^x-x\right)|^1_0=\dfrac{1}{e}+e-2\)