Question

Giúp mik với

Answer 1

a) 2KOH + CO₂ --> K₂CO₃ + H₂O

b)\(n_{CO_2}=\dfrac{1,12}{22,4}=0,05\left(mol\right)\)

PTHH: 2KOH + CO₂ --> K₂CO₃ + H₂O

______0,1<-------0,05------>0,05_____________(mol)

=> 

Answer 2

\(n_{CO_2}=\dfrac{1,12}{22,4}=0,05(mol)\\ a,PTHH:2KOH+CO_2\to K_2CO_3+H_2O\\ b,n_{KOH}=2n_{CO_2}=0,1(mol)\\ \Rightarrow C_{M_{KOH}}=\dfrac{0,1}{0,1}=1M\\ c,n_{K_2CO_3}=n_{CO_2}=0,05(mol)\\ \Rightarrow m_{K_2CO_3}=0,05.138=6,9(g)\)