a)\(=>x=\left(-\dfrac{1}{2}+\dfrac{1}{4}\right):2=-\dfrac{1}{8}\)
bây h mới thấy phần b
\(=>\dfrac{1}{3}\left(x+1\right)=\dfrac{13}{3}-\dfrac{4}{3}=\dfrac{9}{3}=3\)
\(=>x+1=3:\dfrac{1}{3}=9\)
\(=>x=9-1=8\)
a) \(2x-\dfrac{1}{4}=\dfrac{-1}{2}\)
\(2x=\dfrac{-1}{2}+\dfrac{1}{4}\)
\(2x=-\dfrac{1}{4}\)
\(x=-\dfrac{1}{4}\div2\)
\(x=-\dfrac{1}{8}\)
b) \(\dfrac{13}{3}-\dfrac{1}{3}\cdot\left(x+1\right)=\dfrac{4}{3}\)
\(\dfrac{1}{3}\cdot\left(x+1\right)=\dfrac{13}{3}-\dfrac{4}{3}\)
\(\dfrac{1}{3}\cdot\left(x+1\right)=3\)
\(x+1=3\div\dfrac{1}{3}\)
\(x+1=9\)
\(x=9-1\)
\(x=8\)
a) 2x - 1/4 = -1/2 \(\Rightarrow\) -1/2 + 1/4 \(\Rightarrow\) -1/4 \(\Rightarrow\) -1/4 : 2 = -1/2 \(\Rightarrow\) vậy x = ...
b) 13/3 - 1/3 ( x + 1 ) = 4/3 \(\Rightarrow\) 4 ( x + 1 ) = 4/3 \(\Rightarrow\) 4/3 : 4 = 1/3 \(\Rightarrow\) 1/3 - 1 = 1/3 \(\Rightarrow\) vậy x = ...
