Question

Giúp em vs ạ em gấp lắm lun ý =>>

Answer 1

a.\(C\%_{KCl}=\dfrac{20}{600}.100=3,33\%\)

b.2,5kg = 2500g

\(C\%_{Al_2\left(SO_4\right)_3}=\dfrac{34,2}{2500}.100=1,368\%\)

Answer 2

`(a): C%_[KCl] = 20 / 600 . 100 ~~ 3,33 %`

________________________________________

`(b):` Đổi `2,5 kg = 2500 g`

`C%_[Al_2 (SO_4)_3] = [ 34,2 ] / 2500 . 100 = 1,368%`

Answer 3

a. \(C_{\%_{KCl}}=\dfrac{20}{600}.100\%=3,33\%\)

b. \(2,5kg=2500g\)

\(C_{\%_{Al_2\left(SO_4\right)_3}}=\dfrac{34,2}{2500}.100\%=1,368\%\)