\(R=\dfrac{\left(R1+R2\right)\cdot R3}{R1+R2+R3}=\dfrac{\left(2+4\right)\cdot12}{2+4+12}=4\Omega\)
\(U=U12=U3=12V\left(R12//R3\right)\)
\(I12=I1=I2=U12:R12=12:\left(2+4\right)=2A\left(R1ntR2\right)\)
\(I3=U3:R3=12:12=1A\)
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