Question

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Answer 1

\(R_{tđ}=\dfrac{R_1.R_2}{R_1+R_2}=\dfrac{40.60}{40+60}=24\left(\Omega\right)\)

\(I=\dfrac{U}{R_{tđ}}=\dfrac{120}{24}=5\left(A\right)\)

\(U=U_1=U_2=120\left(V\right)\)

\(\left\{{}\begin{matrix}I_1=\dfrac{U_1}{R_1}=\dfrac{120}{40}=3\left(A\right)\\I_2=\dfrac{U_2}{R_2}=\dfrac{120}{60}=2\left(A\right)\end{matrix}\right.\)

Answer 2

\(R_{tđ}=\dfrac{R_1\cdot R_2}{R_1+R_2}=\dfrac{40\cdot60}{40+60}=24\Omega\)

\(I=\dfrac{U}{R}=\dfrac{120}{24}=5A\)

\(I_1=\dfrac{U_1}{R_1}=\dfrac{U}{R_1}=\dfrac{120}{40}=3A\)

\(I_2=5-3=2A\)