Question

giúp e vói ạ

Answer 1

a, \(n_{KClO_3}=\dfrac{36,75}{122,5}=0,3\left(mol\right)\)

PTHH: 2KClO₃ ---t^o→ 2KCl + 3O₂

Mol:        0,3                  0,3      0,45

\(m_{KCl}=0,3.74,5=22,35\left(g\right)\)

\(V_{O_2}=0,45.22,4=10,08\left(l\right)\)

b, 

PTHH: 4Fe + 3O₂ ---t^o→ 2Fe₂O₃

Mol:     0,6     0,45

\(m_{Fe}=0,6.56=33,6\left(g\right)\)