Question

Giúp e với ạ e cần gấp

Answer 1

\(a,\\ n_P=6,2:31=0,2(mol)\\ n_{O_2}=6,72:22,4=0,3(mol)\\ 4P+5O_2\xrightarrow{t^0} 2P_2O_5\\ \dfrac{n_P}{4}<\dfrac{n_{O_2}}{5}\\ \)

\(Nên \ O_2 dư\\ n_{O_2\ dư}=0,3-0,2.5:4=0,05(mol)\\ m_{O_2\ dư}=0,05.32=1,6(g)\\ b, n_{P_2O_5}=0,1(Mol)\\ \Rightarrow m_{P_2O_5}=0,1.142=14,2(g)\)