Question

Giúp đi mai kiểm tra rồi

\(\frac{x}{\sqrt{x+2}}+\sqrt{x+1}=\sqrt{3x+1}\)

Answer 1

<=>\(x+\sqrt{\left(x+1\right)\left(x+2\right)}=\sqrt{3x+1}\)

bình phương 2 vế lên 

\(x^2+\left(x+1\right)\left(x+2\right)+2x\sqrt{\left(x+1\right)\left(x+2\right)}=\left(3x+1\right)\left(x+2\right)\)

Answer 2

khai triển ra ta đc

\(2x^2+2x+2+2x\sqrt{\left(x+1\right)\left(x+2\right)}=3x^2+7x+2\)

<=>\(2x\sqrt{\left(x+1\right)\left(x+2\right)}=2x^2+4x\)

<=>\(x\sqrt{\left(x+1\right)\left(x+2\right)}=x^2+2x\)