\(3\left(-\dfrac{4}{3}\right)^2-\dfrac{7}{3}-0,8.1=3.\dfrac{16}{9}-\dfrac{7}{3}-\dfrac{4}{5}\) = \(\dfrac{16}{3}-\dfrac{7}{3}-\dfrac{4}{5}=3-\dfrac{4}{5}=\dfrac{11}{5}\)
\(\dfrac{9}{25}-\dfrac{4}{5}.\dfrac{64}{25}=\dfrac{9}{25}-\dfrac{256}{125}=\dfrac{-211}{125}\)
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