Question

giúp ạa , camon nhiều ạa 

Answer 1

\(4P+5O_2 \to 2P_2O_5\\ n_P=\frac{3,1}{31}=0,1(mol)\\ n_{O_2}=\frac{5}{32}=0,15625(mol)\\ \text{P hết}, O_2 \text{ dư}\\ a/ \\ m_{O_2}=(0,15625-0,125).32=1(g)\\ b/\\ \text{Chất tạo thành: } P_2O_5\\ n_{P_2O_5}=0,05(mol)\\ m_{P_2O_5}=0,05.142=7,1(g)\)