Ta có: \(\left\{{}\begin{matrix}I1=\dfrac{U1}{R}=\dfrac{24}{R}A\\I2=\dfrac{U2}{R'}=\dfrac{24}{R-2}A\end{matrix}\right.\)
Theo đề bài: \(I2-I1=1A\)
\(\Leftrightarrow\dfrac{24}{R-2}-\dfrac{24}{R}=1\)
\(\Leftrightarrow R\left(R-2\right)=24R-24\left(R-2\right)\)
\(\Leftrightarrow R^2-2R-24R+24R-48=0\)
\(\Leftrightarrow R^2-2R-48=0\)
\(\Leftrightarrow\left[{}\begin{matrix}R=8\Omega\left(nhan\right)\\R=-6\Omega\left(loai\right)\end{matrix}\right.\)