a) Để \(A=\frac{x-2}{3x+2}=0\) thì x-2=0 vì \(3x+2\ne0\)
x-2=0 => x=2
Vậy x=2 thì A=0
b)\(A=\frac{x-2}{3x+2}< 0\Rightarrow\orbr{\begin{cases}x-2< 0\\3x+2< 0\end{cases}\Rightarrow}\orbr{\begin{cases}x< 2\\x< \frac{-2}{3}\end{cases}}\)
\(\Rightarrow x< \frac{-2}{3}\)
Vậy \(x< \frac{-2}{3}\) thì A<0