Question

giair pt: \(\sqrt[3]{x}+\sqrt{5-x}< =3\)

Answer 1

\(\sqrt[3]{x}+\sqrt{5-x}=3\)

Đk:\(0\le x\le5\)

\(pt\Leftrightarrow\sqrt[3]{x}-1+\sqrt{5-x}-2=0\)

\(\Leftrightarrow\frac{x-1}{\sqrt[3]{x}+1}+\frac{5-x-4}{\sqrt{5-x}+2}=0\)

\(\Leftrightarrow\frac{x-1}{\sqrt[3]{x}+1}+\frac{-\left(x-1\right)}{\sqrt{5-x}+2}=0\)

\(\Leftrightarrow\left(x-1\right)\left(\frac{1}{\sqrt[3]{x}+1}-\frac{1}{\sqrt{5-x}+2}\right)=0\)

\(\Rightarrow x=1\). Pt trong ngoặc thì chịu nhưng nghiệm là \(8\sqrt{5}-16\)

Answer 2

à :v sửa tất cả dấu = thành =< nhé nhầm :33