ĐKXĐ : \(x\ge3\)
\(\sqrt{9x-27}-2\sqrt{\frac{x-3}{4}}=1\)
\(\Leftrightarrow\)\(3\sqrt{x-3}-\sqrt{x-3}=1\)
\(\Leftrightarrow\)\(2\sqrt{x-3}=1\)
\(\Leftrightarrow\)\(\sqrt{x-3}=\frac{1}{2}\)
\(\Leftrightarrow\)\(x=\frac{13}{4}\) ( tm đkxđ )
...
ĐKXĐ : \(x\ge3\)
\(\sqrt{9x-27}-2\sqrt{\frac{x-3}{4}}=1\)
\(\Leftrightarrow\)\(3\sqrt{x-3}-\sqrt{x-3}=1\)
\(\Leftrightarrow\)\(2\sqrt{x-3}=1\)
\(\Leftrightarrow\)\(\sqrt{x-3}=\frac{1}{2}\)
\(\Leftrightarrow\)\(x=\frac{13}{4}\) ( tm đkxđ )
...
\(\sqrt{x+3}+2\sqrt{4x+12}-\frac{1}{3}\sqrt{9x+27}=8\)
\(\sqrt{4x^2-4x+1}=\sqrt{x^2+10x+25}\)
Giải pt
giải pt:
a) \(\frac{5\sqrt{x}-2}{8\sqrt{x}+2,5}=\frac{2}{7}\)
b)\(\sqrt{9x^2+12x+4}=4\)
c)\(\sqrt{3-x}-\sqrt{27-9x}+1,25\sqrt{48-16x}-6=0\)
d)\(\sqrt{x^2-10x+25}=2x+2\)
giải phương trình vô tỉ
a) \(\frac{3}{4}\sqrt{x}-\sqrt{9x}+5=\frac{1}{4}\sqrt{9x}\)
b) \(\sqrt{3-x}-\sqrt{27-9x}+1,25\sqrt{48-16x}=6\)
c) \(\sqrt{9x^2+12x+4}=4\)
d) \(\frac{1}{3}\sqrt{x-1}+2\sqrt{4x-4}-12\sqrt{\frac{x-1}{25}}=\frac{29}{15}\)
1)giải pt \(x^3-9x^2+6x-6-3\sqrt[3]{6x^2+2}=0\)
2) giải hệ pt \(\int^{\sqrt{x}\left(1+\frac{3}{x+3y}\right)=2}_{\sqrt{7y}\left(1-\frac{3}{x+3y}\right)=4\sqrt{2}}\)
Giải pt: \(2\sqrt[4]{27x^2+24x+\frac{28}{3}}=1+\sqrt{\frac{27}{2}x+6}\)
2. Giải PT:
a) \(\frac{9x-7}{\sqrt{7x+5}}=\sqrt{7x+5}.\)
b) \(\sqrt{4x-20}+3\sqrt{\frac{x-5}{9}}-\frac{1}{3}\sqrt{9x-45}=4.\)
c) \(2x-x^2+\sqrt{6x^2-12x+7}=0.\)
d) \(\left(x+1\right)\left(x+4\right)-3\sqrt{x^2+5x+2}=6.\)
\(\frac{1}{2}\sqrt{x-1}+\frac{3}{2}\sqrt{9x-9}+24\sqrt{\frac{x-1}{64}}=-17\)
giải pt help me
giải pt
\(\sqrt{x-2}-2\sqrt{4x-8}+4\sqrt{9x-19}=27\)
Giải pt sau:
\(A=\left(\frac{\sqrt{3}}{x^2+x\sqrt{3}+3}+\frac{3}{x^3-\sqrt{27}}\right)\left(\frac{x}{\sqrt{3}}+\frac{\sqrt{3}}{x}+1\right)\)