\(\sqrt{2x+1}-\sqrt{18x+9}=\sqrt{32x+16}-18\left(đk:x\ge-\dfrac{1}{2}\right)\)
\(\Leftrightarrow\sqrt{2x+1}-3\sqrt{2x+1}-4\sqrt{2x+1}=-18\)
\(\Leftrightarrow6\sqrt{2x+1}=18\)
\(\Leftrightarrow\sqrt{2x+1}=3\)
\(\Leftrightarrow2x+1=9\)
\(\Leftrightarrow x=4\left(tm\right)\)
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\(\sqrt{2x+1}-9\sqrt{2x+1}-16\sqrt{2x+1}=-18\)
\(-24\sqrt{2x+1}=-18\)
\(\sqrt{2x+1}=\dfrac{3}{4}\)
\(\sqrt{\left(2x+1\right)^2}=\dfrac{9}{16}\)
\(2x+1=\dfrac{9}{16}\)
\(x=\dfrac{-7}{32}\)
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