Sửa lại đề \(\frac{x+1}{x-1}+\frac{x-2}{x+2}+\frac{x-3}{x+3}+\frac{x+4}{x-4}=-4\)
ĐK \(x\ne\left\{1;-2;-3;4\right\}\)
\(\Leftrightarrow\left(\frac{x+1}{x-1}+1\right)+\left(\frac{x-2}{x+2}+1\right)+\left(\frac{x-3}{x+3}+1\right)+\left(\frac{x+4}{x-4}+1\right)=0\)
\(\Leftrightarrow\frac{2x}{x-1}+\frac{2x}{x+2}+\frac{2x}{x+3}+\frac{2x}{x-4}=0\)
\(\Leftrightarrow2x\left(\frac{1}{x-1}+\frac{1}{x+2}+\frac{1}{x+3}+\frac{1}{x-4}\right)=0\Leftrightarrow x=0\)vì \(\frac{1}{x-1}+\frac{1}{x+2}+\frac{1}{x+3}+\frac{1}{x-4}\ne0\)
Vậy pt có nghiệm \(x=0\)
cô giáo in đề cho mk là =4 mà
nếu k thì mk xong lâu r
