Question

Giải PT

\(\frac{x+11}{115}+\frac{x+22}{104}=\frac{x+33}{93}+\)\(\frac{x+44}{82}\)

 

 

Answer 1

Ta có: \(\frac{x+11}{115}+\frac{x+22}{104}=\frac{x+33}{93}+\frac{x+44}{82}\)

\(\Rightarrow\left(\frac{x+11}{115}+1\right)+\left(\frac{x+22}{104}+1\right)=\left(\frac{x+33}{93}+1\right)+\left(\frac{x+44}{82}+1\right)\)

\(\Rightarrow\frac{x+126}{115}+\frac{x+126}{104}=\frac{x+126}{93}+\frac{x+44}{82}\)

\(\Rightarrow\frac{x+126}{115}+\frac{x+126}{104}-\frac{x+126}{93}-\frac{x+126}{82}=0\)

\(\Rightarrow\left(x+126\right).\left(\frac{1}{115}+\frac{1}{104}+\frac{1}{93}+\frac{1}{82}\right)=0\)

\(\Rightarrow x+126=0\)( vì \(\frac{1}{115}+\frac{1}{104}+\frac{1}{93}+\frac{1}{82}\ne0\) )

\(\Rightarrow x=-126\)

vậy \(x=-126\)