\(\dfrac{4-x}{96}+1+\dfrac{3-x}{97}+1=\dfrac{2-x}{98}+1+\dfrac{1-x}{99}+1\)
\(\Leftrightarrow\dfrac{100-x}{96}+\dfrac{100-x}{97}-\dfrac{100-x}{98}-\dfrac{100-x}{99}=0\)
\(\Leftrightarrow\left(100-x\right)\left(\dfrac{1}{96}+\dfrac{1}{97}-\dfrac{1}{98}-\dfrac{1}{99}\right)=0\Leftrightarrow x=100\)
\(\dfrac{x-1}{99}-\dfrac{x+1}{101}+\dfrac{x-2}{98}-\dfrac{x+2}{102}+\dfrac{x-3}{97}-\dfrac{x+3}{103}+\dfrac{x-4}{96}-\dfrac{x+4}{104}=0\)
Tính : \(\dfrac{x-1}{98}+\dfrac{x-2}{97}+\dfrac{x-3}{96}=\dfrac{x-4}{93}+2\)
\(\left(\dfrac{x+2}{98}+1\right)+\left(\dfrac{x+3}{97}+1\right)=\left(\dfrac{x+4}{96}+1\right)+\left(\dfrac{x+5}{95}+1\right)\)
Giải các pt sau:
1)\(\dfrac{2x+1}{x^2-4}+\dfrac{2}{x+1}=\dfrac{3}{2-x}\)
2)\(\dfrac{3x+1}{1-3x}+\dfrac{3+x}{3-x}=2\)
3)\(\dfrac{8x-2}{3}=1+\dfrac{5-2x}{4}\)
4)
\(\dfrac{x}{x+1}-\dfrac{2x+3}{x}=\dfrac{-3}{x+1}-\dfrac{3}{x}\)
5)\(\dfrac{x+1}{x-1}-\dfrac{x-1}{x+1}=\dfrac{4}{x^2-1}\)
6)\(\dfrac{2x+5}{2x}-\dfrac{x}{x+5}=0\)
giúp mình với cám ơn
Giải PT (X+1)/99+(X+2)/98+(X+3)/97+(X+4)/96 = -4
Giải PT sau:
\(\dfrac{x}{3}-\dfrac{2x+1}{2}=\dfrac{x}{6}-\dfrac{x}{4}\)
\(\dfrac{x-1}{x-2}+\dfrac{x+3}{x-4}=\dfrac{2}{-x^2+6x-8}\)
Giải pt
giải pt sau
a)\(\dfrac{60}{x}=\dfrac{4}{3}+\dfrac{60-x}{x+4}\)
b)\(\dfrac{100}{x}-\dfrac{100}{x+20}=\dfrac{5}{6}\)
c)\(\dfrac{2x+1}{2x-1}-\dfrac{2x-1}{2x+1}=\dfrac{8}{4x^2-1}\)
Helppppp
$a)\dfrac{x-3}{x-2}+$$\dfrac{x-2}{x-4}=-1$
Giải pt
