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haizz
\(6x^4+7x^3-36x^2-7x+6=0\)
\(\Leftrightarrow\left(6x^4-11x^3-3x^2+2x\right)+\left(18x^3-33x^2-9x+6\right)=0\)
\(\Leftrightarrow x\left(6x^3-11x^2-3x+2\right)+3\left(6x^3-11x^2-3x+2\right)=0\)
\(\Leftrightarrow\left(6x^3-11x^2-3x+2\right)\left(x+3\right)=0\)
\(\Leftrightarrow\left[\left(6x^3-14x+4x\right)+\left(3x^2-7x+2\right)\right]\left(x+3\right)=0\)
\(\Leftrightarrow\left[2x\left(3x^2-7x+2\right)+\left(3x^2-7x+2\right)\right]\left(x+3\right)=0\)
\(\Leftrightarrow\left(3x^2-7x+2\right)\left(2x+1\right)\left(x+3\right)=0\)
\(\Leftrightarrow\left(3x^2-6x-x+2\right)\left(2x+1\right)\left(x+3\right)=0\)
\(\Leftrightarrow\left[3x\left(x-2\right)-\left(x-2\right)\right]\left(2x+1\right)\left(x+3\right)=0\)
\(\Leftrightarrow\left(x-2\right)\left(3x-1\right)\left(2x+1\right)\left(x+3\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x-2=0\\3x-1=0\end{cases}}\)hoặc \(\orbr{\begin{cases}2x+1=0\\x+3=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=2\\x=\frac{1}{3}\end{cases}}\)hoặc\(\orbr{\begin{cases}x=\frac{-1}{2}\\x=-3\end{cases}}\)
Vậy tập hợp nghiệm \(S=\left\{2;-3;\frac{1}{3};\frac{-1}{2}\right\}\)
