Ta có \(4-\left|2x+1\right|=3x+3\)
\(\Leftrightarrow\left|2x+1\right|=3x+1\)
\(\Leftrightarrow\hept{\begin{cases}-2x-1=3x+1\\2x+1=3x+1\end{cases}\Leftrightarrow\hept{\begin{cases}-5x=2\\-x=0\end{cases}\Leftrightarrow}\hept{\begin{cases}x=-\frac{2}{5}\\x=0\end{cases}}}\)(tm)
Vậy BFT có nghiệm ....
