\(\Leftrightarrow x\left(x+1\right)\left(x-2\right)\left(x-3\right)=4\)
\(\Leftrightarrow\left(x^2-2x\right)\left(x^2-2x-3\right)=4\)
Đặt \(x^2-2x=t\)
\(\Rightarrow t\left(t-3\right)=4\)
\(\Leftrightarrow t^2-3t-4=0\Rightarrow\left[{}\begin{matrix}t=-1\\t=4\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x^2-2x=-1\\x^2-2x=4\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x^2-2x+1=0\\x^2-2x-4=0\end{matrix}\right.\) (bấm máy)
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