Question

Giải pt: x⁴-4x³+8x-5=0

AI NHANH MÌNH TICK Ạ

 

Answer 1

\(x^4-4x^3+8x-5=0\\ \Leftrightarrow-3x+8x-5=0\\ \Leftrightarrow5x-5=0\\ \Leftrightarrow5x=5\\ \Leftrightarrow x=1.\)

Answer 2

x4−4x3+8x−5=0

⇔x4−x3−3x3+3x+5x−5

=0;l

⇔(x−1)(x3−3x2−3x+5)

=0;l

⇔(x−1)2⋅(x2−2x−5)=0

⇔⎡x=1

⎡x=√6+1

⎡x=−√6+1