\(x^3+9x^2+27x+27=x^3+3x^2+6x^2+18x+9x+27=x^2\left(x+3\right)+6x\left(x+3\right)+9\left(x+3\right)\)
\(=\left(x^2+6x+9\right)\left(x+3\right)=\left(x+3\right)^2\left(x+3\right)=\left(x+3\right)^3=0\)
=>x+3=0=>x=-3
cho biểu thức
P=(\(\dfrac{\text{x^3+3x}}{\text{x^3+3x^2+9x+27}}\)+\(\dfrac{\text{3}}{\text{x^2+9}}\)):(\(\dfrac{\text{1}}{\text{x-3}}\)-\(\dfrac{\text{6x}}{\text{x^3-3x^2+9x-27}}\))
rút gọn p
với x>0 thì P không nhận gt nào
Tìm cácgt của x để P nguyên
giai pt x^2 + (9x^2)/(x+3)^2=27
giai pt x^2 + (9x^2)/(x+3)^2=27
tìm GTNN
C=\(\dfrac{x^6+27}{\text{x}^4-3x^3+6x^2-9x+9}\)
Tìm x :
a) X mũ 2 . ( x+2)-9x -18 = 0
b) 9x -27 - x mũ hai . ( x-3)=0
Giải pt :
(3x-2)(9x2+6x+4)-(3x-1)(9x2-3x+1)=x-4
9(2x+1)=4(x-5)2
x3-4x2-12x+27=0
MN giúp mk vs ! Sắp nộp r o(╥﹏╥)o
Giải pt :
(3x-2)(9x2+6x+4)-(3x-1)(9x2-3x+1)=x-4
9(2x+1)=4(x-5)2
x3-4x2-12x+27=0
MN giúp mk vs ! Sắp nộp r o(╥﹏╥)o
Tìm x:
a) x3-9x2+27x-27=0
b) x3-25x=0
c)9x2-1=0
Giải pt sau
\(\dfrac{1}{\text{x}^2+5x+6}\)+\(\dfrac{1}{\text{x}^2+7x+12}\)+\(\dfrac{1}{x^2+9x +12}\)+\(\dfrac{1}{\text{x}^2+9x+30}=\dfrac{1}{8}\)
