Question

giải PT sau:

\(\frac{1}{x-2}+\frac{3}{6-x}=2\)

thank.hi

Answer 1

\(\frac{6-x}{\left(x-2\right)\left(6-x\right)}+\frac{3\left(x-2\right)}{\left(x-2\right)\left(6-x\right)}=\frac{2\left(x-2\right)\left(6-x\right)}{\left(x-2\right)\left(6-x\right)}\) rồi khử mẫu đi rồi tính