ta có: \(5x-3y=2xy-11\)
<=>\(2x-2xy+3-3y+3x=-8\)
<=>\(2x\left(1-y\right)+3\left(1-y\right)+\frac{3}{2}\left(2x+3\right)=-\frac{7}{2}\)
<=>\(\left(2x+3\right)\left(1-y\right)+\frac{3}{2}\left(2x+3\right)=-\frac{7}{2}\)
<=>\(\left(2x+3\right)\left(1-y+\frac{3}{2}\right)=-\frac{7}{2}\)
<=>\(\left(2x+3\right)\left(2-2y+3\right)=-7\)
TH1: \(\hept{\begin{cases}2x+3=1\\2-2y+3=-7\end{cases}\Rightarrow\hept{\begin{cases}x=-1\\y=6\end{cases}}}\)
TH2:\(\hept{\begin{cases}2x+3=-1\\2-2y+3=7\end{cases}\Rightarrow\hept{\begin{cases}x=-2\\y=-1\end{cases}}}\)
TH3:\(\hept{\begin{cases}2x+3=7\\2-2y+3=-1\end{cases}\Rightarrow\hept{\begin{cases}x=2\\y=3\end{cases}}}\)
TH4:\(\hept{\begin{cases}2x+3=-7\\2-2y+3=1\end{cases}\Rightarrow\hept{\begin{cases}x=-5\\y=2\end{cases}}}\)
Vậy nghiệm của pt là: (x;y)={ (-1;6);(-2;-1);(2;3);(-5;2)}
