Đặt \(\hept{\begin{cases}x-\frac{9}{2}=a\\x-\frac{11}{4}=b\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}a^4+b^4=1\\a=b-\frac{7}{4}\end{cases}}\)
\(\Rightarrow\left(b-\frac{7}{4}\right)^4+b^4-1=0\)
Giờ chứng minh nó vô nghiệm thôi
Giải pt sau :\(\frac{25}{x}+9\sqrt{9x^2-4}=\frac{2}{x}+\frac{18}{x^2+1}\)
B2: Cho x;y >0 .Tìm min \(B=\left(3+\frac{1}{x}\right)\left(3+\frac{1}{y}\right)\left(2+x+y\right)\)
Giải PT \(\frac{1}{11}\left(17-3\sqrt{x-1}\right)=\frac{1}{15}\left(23-4\sqrt{x-1}\right)\)
Giải pt: \(\frac{x^2}{3+\sqrt{9-x^2}}+\frac{1}{4\left(3-\sqrt{9-x^2}\right)}=1\)
Giải pt: \(\left(x+1\right)\left(x+4\right)+3\left(x-4\right)\sqrt{\frac{x+1}{x+4}}-18=0\)
Giải pt: \(\left(\frac{x+2}{x+1}\right)^2+\left(\frac{x-2}{x-1}\right)^2-\frac{5x^2-4}{2x^2-1}=0\)
Giải pt \(\left(\frac{x+2}{x+1}\right)^2+\left(\frac{x-2}{x-1}\right)-\frac{5x^2-4}{2x^2-1}=0\)
giải pt
\(\frac{2\left(x-\sqrt{2}\right)\left(x-\sqrt{3}\right)}{\left(1-\sqrt{2}\right)\left(1-\sqrt{3}\right)}+\frac{3\left(x-1\right)\left(x-\sqrt{3}\right)}{\left(\sqrt{2}-1\right)\left(\sqrt{2}-\sqrt{3}\right)}+\frac{4\left(x-1\right)\left(x-\sqrt{2}\right)}{\left(\sqrt{3}-1\right)\left(\sqrt{3}-2\right)}\)=3x-1
GIẢI PT \(3\left(\frac{x+3}{x-2}\right)^2+168\left(\frac{x-3}{x+2}\right)^2-46\frac{x^2-9}{x^2-4}=0\)
Giải pt
\(\frac{1}{7x+1}+\frac{1}{\sqrt{\left(7x+11\right)\left(9-7x\right)}}=\frac{7}{24}\left(x\inℝ\right)\)
