Question

giải pt : 

\(\frac{\left(x+3\right)\left(x-3\right)}{3}+2=x\left(1-x\right)\)

Answer 1

\(\Rightarrow\left(x+3\right)\left(x-3\right)+6=3x\left(1-x\right)\)

\(\Rightarrow x^2-9+6=3x-3x^2\)

\(\Rightarrow4x^2-3x-3=0\)

Có: \(\Delta=\left(-3\right)^2-4.\left(-3\right).4=57>0\)

\(\Rightarrow\sqrt{\Delta}=\sqrt{57}\)

\(\Rightarrow x=\frac{3+\sqrt{57}}{8}\) hoặc \(x=\frac{3-\sqrt{57}}{8}\)

Vậy có 2 nghiệm .....

Answer 2

ai tick mk mình tick lại 3 cái