\(a\left(a-5\right)-2\left(a-5\right)a=18\)
\(\Leftrightarrow a^2-5a-2a^2+10a-18=0\)
\(\Leftrightarrow-a^2+5a-18=0\)
\(\Delta=b^2-4ac=5^2-4.\left(-1\right).\left(-18\right)=-72< 0\)
\(\Leftrightarrow\)pt vô nghiệm
Vậy \(S=\varnothing\)
\(a\left(a-5\right)-2a\left(a-5\right)=18\)
\(a^2-5a-2a^2+10a=18\)
\(-a^2+5a-18=0\)
Ta có: \(\text{∆}=5^2-4.18=-47\)
Vì ∆<0 => pt vô nghiệm