Question

Giải pt: \(8x^2+\sqrt{10x+11}+\sqrt{14x+18}=11\)

Answer 1

\(\Leftrightarrow\sqrt{14x+18}+\sqrt{10x+11}+8x^2=11\)

\(\Rightarrow\sqrt{14x+18}+\sqrt{10x+11}+8x^2-11=0\)

\(\Rightarrow-\frac{\sqrt{-\sqrt{14x+18}-\sqrt{10x+11}+11}-\sqrt{2^3}x}{\sqrt{2^3}}=0\)

\(\Rightarrow\sqrt{-\sqrt{14x+18}-\sqrt{10x+11}+11}-\sqrt{2^3}x=0\)

\(\Rightarrow\frac{\sqrt{-\sqrt{14x+18}-\sqrt{10x+11}+11}+\sqrt{2^3}x}{\sqrt{2^3}}=0\)

\(\Rightarrow\sqrt{-\sqrt{14x+18}-\sqrt{10x+11}+11}+\sqrt{2^3}x=0\)

=>2x=1

=>x=-1

=>x=1:2=\(\frac{1}{2}\)

 

Answer 2

bấm mày tính ra x=-1 hoặc \(\frac{1}{2}\)

Answer 3

cần làm hộ ko

Answer 4

ket qua x = -1 hoac 1/2 ban nha

Answer 5

hiểu chết liền á