Question

Giải pt \(3\sqrt{5x-1}-9\sqrt{9x+7}=2\sqrt{x+2}\)
giúp vs ạ!!!!!!!!!!!!!!!!!!!!

Answer 1

hình như đề sai bấm máy ra can't solve

Answer 2

ĐK: \(x\ge\frac{1}{5}\)

bạn chuyển vế rồi bình phương

Answer 3

Giải pt \(3\sqrt{5x-1}-\sqrt{9x+7}=2\sqrt{x+2}\)
giúp vs ạ!!!!!!!!!!!!!!!!!!!!

Answer 4

\(3\sqrt{5x-1}-\sqrt{9x+7}-2\sqrt{x+2}=0 \)
\(3\left(\sqrt{5x-1}-3\right)-\left(\sqrt{9x+7}-5\right)-2\left(\sqrt{x+2}-2\right)=0\)
\(3\frac{5x-1-9}{\sqrt{5x-1}+9}-\frac{9x+7-25}{\sqrt{9x+7}+5}-2\frac{x+2-4}{\sqrt{x+2}+2}=0 \)
\(3\frac{5\left(x-2\right)}{\sqrt{5x-1}+9}-\frac{9.\left(x-2\right)}{\sqrt{9x+7}+5}-2\frac{x-2}{\sqrt{x+2}+2}=0 \)
\(\left(x-2\right).\left(\frac{15}{\sqrt{5x-1}+9}-\frac{9}{\sqrt{9x+7}+5}-\frac{1}{\sqrt{x+2}+2}\right)=0\)
\(\frac{15}{\sqrt{5x-1}+9}-\frac{9}{\sqrt{9x+7}+5}-\frac{1}{\sqrt{x+2}+2}\ne0\)
=>x-2=0=>x=2