(x-3/2011)-1+(x-2/2012)-1 = (x-2012/2)-1+(x-2011/3)-1
x-2014/2011+x-2014/2012 = x-2014/2+x-2014/ 3
(x-2014)(1/2011+1/2012-1/2-1/3)=0
x-2014 =0 [vì (1/2011+ 1/2012-1/2-1/3#0)]
x=2014
\(\Leftrightarrow\frac{4023x-10058}{4046132}=\frac{5x-10056}{6}\Rightarrow\left(4023x-10058\right)6=4046132\left(5x-10058\right)\)
<=>(4023x-10058)6=6(4023x-10058)
=>6(4023x-10058)=4046132(5x-10058)
=>24138x-60348=20230660x-40695995656
=>-20206522x=-40695935308
=>x=(-40695935308):(-20206522)
=>x=2014