Question

giải phương trình

\(\sqrt{x}+\sqrt{1-x}+2\sqrt{x-x^2}-2\sqrt[4]{x-x^2}=1\)

\(\sqrt{x^2+10x+7}=3\sqrt{x+3}+2\sqrt{x+7}-6\)

\(\sqrt[3]{x+1}+\sqrt[3]{x+2}=1+\sqrt[3]{x-3x+12}\)

\(\left(4x+2\right)\sqrt{x+8}=3x^2+7x+8\)

\(x+4\sqrt{5-x}=4\sqrt{x-1}+\sqrt{-x^2+6x-5}+1\)

Answer 1

giải phương trình$\sqrt{x}+\sqrt{1-x}+2\sqrt{x-x^2}-2\sqrt[4]{x-x^2}=1$√x+√1−x+2√x−x2−24√x−x2=1$\sqrt{x^2+10x+7}=3\sqrt{x+3}+2\sqrt{x+7}-6$√x2+10x+7=3√x+3+2√x+7−6$\sqrt[3]{x+1}+\sqrt[3]{x+2}=1+\sqrt[3]{x-3x+12}$3√x+1+3√x+2=1+3√x−3x+12$\left(4x+2\right)\sqrt{x+8}=3x^2+7x+8$(4x+2)√x+8=3x2+7x+8$x+4\sqrt{5-x}=4\sqrt{x-1}+\sqrt{-x^2+6x-5}+1$x+ 

ải phương trình

$\sqrt{x}+\sqrt{1-x}+2\sqrt{x-x^2}-2\sqrt[4]{x-x^2}=1$√x+√1−x+2√x−x2−24√x−x2=1

4√5−x=4√x−1+√−x2+6x−5+1