Question

giải phương trình\(\left(x-1\right)\cdot\left(x^2+3x-2\right)-\left(x^3-1\right)=0\)

Answer 1

(x-1)(x^2+3x-2-x^2-x-1)=(x-1)(2x-3)=0=> x=1 hoăc x=3/2

Answer 2

(x-1)(x²+3x-2)-(x³-1)=0

<=>(x-1)(x²+3x-2)-(x-1)(x²+x+1)=0

<=>(x-1)(x²+3x-2-(x²+x+1))=0

<=>(x-1)(x²+3x-2-x²-x-1)=0

<=>(x-1)(2x-3)=0

<=>x-1=0 hay 2x-3=0

<=>x=1 hay x=\(\frac{3}{2}\)