\(\left(\frac{1}{1.51}+\frac{1}{2.52}+\frac{1}{3.53}+...+\frac{1}{10.60}\right).x=\frac{1}{1.11}+\frac{1}{2.12}+...+\frac{1}{50.60}\)
\(\Leftrightarrow\left(\frac{50}{1.51}+\frac{50}{2.52}+...+\frac{50}{10.60}\right).x=5.\left(\frac{10}{1.11}+\frac{10}{2.12}+...+\frac{10}{50.60}\right)\)
\(\Leftrightarrow\left(1-\frac{1}{51}+\frac{1}{2}-\frac{1}{52}+...+\frac{1}{10}-\frac{1}{60}\right).x=5.\left(1-\frac{1}{11}+\frac{1}{2}-\frac{1}{12}+...+\frac{1}{50}-\frac{1}{60}\right)\)
\(\Leftrightarrow\left[\left(1+\frac{1}{2}+...+\frac{1}{10}\right)-\left(\frac{1}{51}+\frac{1}{52}+...+\frac{1}{60}\right)\right].x=5.\left[\left(1+\frac{1}{2}+...+\frac{1}{10}\right)-\left(\frac{1}{51}+\frac{1}{52}+..+\frac{1}{60}\right)\right]\)
\(\Leftrightarrow x=5\)