(x+2/2008+1)+(x+3/2007+1)+(x+4/2006+1)+(x+2028/6-3)=0
=x+2010/2008+ x+2010/2007+ x+2010/2006+ x+2010/6=0
=(x+2010)(1/2008+1/2007+1/2006+1/6)=
VÌ 1/2008 +1/2007 +1/2006+1/6 khác 0
=>x+2010=0=>x=-2010
(x+2/2008+1)+(x+3/2007+1)+(x+4/2006+1)+(x+2028/6-3)=0
=x+2010/2008+ x+2010/2007+ x+2010/2006+ x+2010/6=0
=(x+2010)(1/2008+1/2007+1/2006+1/6)=
VÌ 1/2008 +1/2007 +1/2006+1/6 khác 0
=>x+2010=0=>x=-2010
giải phương trình hộ nhé
\(\frac{x+2}{2008}+\frac{x+3}{2007}+\frac{x+4}{2006}+\frac{x+2028}{6}=0\)
giải phương trình sau
\(\frac{x+2}{2008}+\frac{x+3}{2007}+\frac{x+4}{2006}+\frac{x+2028}{6}=0\) O
\(\frac{x+2}{2008}+\frac{x+3}{2007}+\frac{x+4}{2006}+\frac{x+2028}{6}=0\)0
2x(x+2)^2-8x^2=2(x-2)(x^2+2x+4)
\(\frac{x+2}{2008}+\frac{x+3}{2007}+\frac{x+4}{2006}+\frac{x+2028}{6}\)
giải các phương trình sau:
)\(\frac{x+1}{2008}+\frac{x+2}{2007}+\frac{x+3}{2006}=\frac{x+4}{2005}+\frac{x+5}{2006}+\frac{x+6}{2003}\)
giải phương trình sau :
\(\frac{x+1}{2008}+\frac{x+2}{2007}+\frac{x+3}{2006}=\frac{x+4}{2005}+\frac{x+5}{2004}+\frac{x+6}{2003}\)
Giải phương trình :
a) \(\left(x^2+x\right)^2+4\left(x^2+x\right)=12\)
b) \(\frac{x+1}{2008}+\frac{x+2}{2007}+\frac{x+3}{2006}=\frac{x+4}{2005}+\frac{x+5}{2004}+\frac{x+6}{2003}\)
c) \(6x^4-5x^3-38x^2-5x+6=0\)
Giải phương trình sau:
x+2/2008 + x+3/2007 + x+4/2006 + x+2028/6 =0
Giải phương trình:
1. \(\left(x^2+x\right)^2+4\left(x^2+x\right)^2=12\)
2. \(\frac{x+1}{2008}+\frac{x+2}{2007}+\frac{x+3}{2006}=\frac{x+4}{2005}+\frac{x+5}{2004}+\frac{x+6}{2003}\)