Lời giải:
$\frac{x+16}{49}+\frac{x+1}{47}=-1$
$\frac{x+16}{49}+\frac{x+1}{47}+1=0$
$\frac{x+16}{49}+\frac{x+48}{47}=0$
$\frac{x+16}{49}=\frac{x+48}{-47}$
$-47(x+16)=49(x+48)$
$-47x-752 = 49x+2352$
$-752-2352=49x+47x$
$-3104=96x$
$x=\frac{-3104}{96}=\frac{-97}{3}$