Question

Giải phương trình

(2-3x)*(x+11)=(3x-2)*(2-5x)

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Answer 1

 (2-3x)(x+11)=(3x-2)(2-5x)

<=> (2-3x)(x+11)-(3x-2)(2-5x)=0

<=> (2-3x)(x+11)+(2-3x)(2-5x)=0

<=> (2-3x)(x+11+2-5x)=0

<=> (2-3x)(-4x+13)=0

TH1: 2-3x=0

<=> x=2/3

TH2: -4x+13=0

<=>x=13/4

chúc bạn học tốt

Answer 2

(2-3x)(x+11)=(3x-2)(2-5x)

\(\Leftrightarrow\)(2-3x)(x+11)-(3x-2)(2-5x)=0

\(\Leftrightarrow\)(2-3x)(x+11)+(2-3x)(2-5x)=0

\(\Leftrightarrow\)(2-3x)(x+11+2-5x)=0

\(\Leftrightarrow\)(2-3x)(13-4x)=0

\(\Leftrightarrow\)\(\hept{\begin{cases}2-3x=0\\13-4x=0\end{cases}\Rightarrow\hept{\begin{cases}x=\frac{2}{3}\\x=\frac{13}{4}\end{cases}}}\)

Chúc bạn học tốt :))

Answer 3

mik nha 

Ta có: (2-3x)(x+11)=(3x-2)(2-5x)

           2x-3x²+22-33x=6x-4-15x²+10x

           2x-3x²+22-33x-6x+4+15x²-10x=0

           12x²-47x+26=0

           12x²-8x-39x+26=0

           (3x-2)(4x-13)=0

      => 3x-2=0=>x=2/3

hoặc  4x-13=0=>x=13/4

Vậy S={2/3;13/4}