\(\sqrt{9\left(x-2\right)^2}+2x=\sqrt{x-1}\left(ĐK:x\ge1\right)\)
<=> \(\left|9\left(x-2\right)\right|+2x=\sqrt{x-1}\)
<=> \(\left[{}\begin{matrix}-9\left(x-2\right)+2x=\sqrt{x-1}\\9\left(x-2\right)+2x=\sqrt{x-1}\end{matrix}\right.\)
<=> \(\left[{}\begin{matrix}2,40.....\left(TM\right)\\1,71....\left(TM\right)\end{matrix}\right.\)