Question

giải phương trình sau 

(2x-2)^2 =(x+1)^2 +3(x-2)(x+5)

 

 

Answer 1

(2x-2)^2=(x+1)^2+3(x-2)(x+5)

(2x-2)^2-(x+1)^2=3(x-2)(x+5)

(2x-2-x-1)(2x-2+x+1)=3(x^2+5x-2x-10)

(x-3)(3x-1)=3(x^2+3x-10)

3x^2-x-9x+3=3x^2+9x-30

-19x+33=0

-19x=-33

x=33/19

Answer 2

(2x- 2)² = (x+1)² + 3(x-2)(x+5)

<=> 4x-4= x² +1+3x-6+3x+15

<=> -4+6-1+15=(-4x+3x+3x)+x²

<=> -14=2x+x²

^{mk chi tra loi dc den do thui. co j thong cam nha}

Answer 3

de mk suy nghi them da nha 

Answer 4

tiep khuc do nha

<=>x²+2x+14

viet ca khuc do vao roi tiep den cai nay nha

Answer 5

mk cung ko pit la dung hay sai nua. neu sai thi may bn sua giup bn ay nha