Question

Giải phương trình nghiệm nguyên sau:

a, 6x-8y=9

b, 11x+18y120

c, 17x-39y=4

Answer 1

a,\(6x-8y=9\)

\(\Rightarrow x=\frac{9+8y}{6}\)

\(y=\frac{6x-9}{8}\)

Vậy....

Answer 2

\(b,11x+18y=120\)

\(\Rightarrow x=\frac{120-18y}{11}\)

\(y=\frac{120-11x}{18}\)

Answer 3

\(c,17x-39y=4\)

\(\Rightarrow x=\frac{4+39y}{17}\)

\(y=\frac{17x-4}{39}\)