Question

giải phương trình :\(\frac{x^2}{\sqrt{3x-2}}-\sqrt{3x-2}=1-x\)

Answer 1

quy đồng lên bạn ơi , rồi đặt ẩn

Answer 2

\(\Leftrightarrow x^2-3x+2=\left(1-x\right)\sqrt{3x-2}\)

\(\Leftrightarrow\left(x-2\right)\left(x-1\right)=-\left(x-1\right)\sqrt{3x-2}\)

\(\Leftrightarrow x-2=-\sqrt{3x-2}\)

\(\Leftrightarrow x^2-4x+4=3x-2\Leftrightarrow x=6;x=1\left(\text{nhận cả 2}\right)\)

Vậy................

Answer 3

mình ko biết

Answer 4

\(\frac{x^2-3x+2}{\sqrt{3x-2}}+\left(x-1\right)=0\)

\(\left(x-1\right)\left(\frac{x-2}{\sqrt{3x-2}}+1\right)=0\)

Answer 5

\(\frac{x^2}{\sqrt{3x-2}}-\frac{3x-2}{\sqrt{3x-2}}=\frac{\left(\sqrt{3x-2}\right)\left(1-x\right)}{\sqrt{3x-2}}\)

\(x^2-3x+2+\sqrt{x^2-3x+2}=0\)

\(\sqrt{x^2-3x+2}\left(\sqrt{x^2-3x+2}+1\right)=0\)\(\sqrt{x^2-3x+2}=0hay\sqrt{x^2-3x+2}+1=0\left(vl\right)\)

còn lại tự làm nhé