Các câu hỏi tương tự
Tìm x để B=3A,biếtA=\(\left(\frac{5+2\sqrt{6}}{\sqrt{3}+\sqrt{2}}+\frac{5-2\sqrt{6}}{\sqrt{3}-\sqrt{2}}\right)\) /\(\left(\frac{1}{2\sqrt{5}+3\sqrt{2}}-\frac{1}{2\sqrt{5}-3\sqrt{2}}\right)\)
B=\(\frac{2x^4-x^3+2x^2+x-4}{2x^3-x^2-2x+1}\)
Rút gọn:
\(A=\left(\frac{4x\sqrt{x}+3x+9}{x+5\sqrt{x}+6}-\frac{3-\sqrt{x}}{2+\sqrt{x}}\right)\div\left(\frac{\sqrt{x}}{3+\sqrt{x}}-\frac{3+4\sqrt{x}}{x+5\sqrt{x}+6}\right)\)
\(B=\left(x-\sqrt{x}-2\right)\left(\dfrac{3}{\sqrt{x}-2}-\dfrac{4-\sqrt{x}}{x-2\sqrt{x}}\right)\)
Rút gọn:
\(A=\left(\frac{2+\sqrt{x}}{x-5\sqrt{x}+6}-\frac{\sqrt{x}+3}{2-\sqrt{x}}-\frac{\sqrt{x}+2}{\sqrt{x}-3}\right):\left(2-\frac{\sqrt{x}}{1+\sqrt{x}}\right)\)
rút gọn:\(\frac{\sqrt{15}-\sqrt{5}}{\sqrt{3}-4}+\frac{5-2\sqrt{5}}{2\sqrt{5}-4}\)
Xem chi tiết
\(\left(1+\frac{11-\sqrt{11}}{1-\sqrt{11}}\right)\left(\frac{11+\sqrt{11}}{1+\sqrt{11}}+1\right)\)
Giải phương trình:
a) \(\sqrt{1-x^2}=\left(\frac{2}{3}-\sqrt{x}\right)^2\)
b) \(\sqrt{x^2+15}=3\sqrt[3]{x}+\sqrt{x^2+8}-2\)
c) \(x+\frac{3x}{\sqrt{1+x^2}}=1\)
d) \(3x+\sqrt{x^2+5}-\sqrt{x^2+12}-5=0\)
1,826-y/\(1,826-\frac{y^2}{\sqrt{12,04}}:\sqrt{18}\cdot\left(\sqrt{15}-\frac{2,3+\frac{5}{3\sqrt{5}}\cdot7}{0,0598\sqrt{15}+\sqrt[3]{6}}\right)=\frac{7}{4}\)
16 tháng 8 2020 lúc 21:18
Giải bất phương trình sau :
\(\frac{\sqrt{x^2-x+6}+7\sqrt{x}-\sqrt{6\left(x^2+5x-2\right)}}{x+3-\sqrt{2\left(x^2+10\right)}}\le1\)
\(A=\left(\frac{3\sqrt{x}+6}{x-4}+\frac{\sqrt{x}}{\sqrt{x}-2}\right):\frac{x-9}{\sqrt{x}-3}a:Rutgon;b:TìmxđểA=\frac{1}{5}\)
\(A=\left(\sqrt{3}+1\right)^2+\frac{5}{4}\sqrt{48}-\frac{2}{\sqrt{3+1}}\)
\(B=\frac{4}{3-\sqrt{5}}-\frac{3}{\sqrt{5}+\sqrt{2}}-\frac{1}{\sqrt{2}-1}\)
\(C=\sqrt{4-2\sqrt{3}}-\sqrt{7+4\sqrt{3}}\)
Rút gọn
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