PT
\(log2^{x^2-x}+log3^{x^2-x}=log2.5^{x^2-x}\)
\(\Leftrightarrow x^2-xlog2+x^2-xlog3=2\left(x^2-x\right)log5\)
\(\Leftrightarrow\left(x^2-x\right)\left(log2+log3-2log5\right)=0\)
\(\Leftrightarrow x^2-x=0\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=1\end{cases}}\)
Vay nghiem cua PT la \(x=0\)va \(x=1\)