Ta có: \(\left(2x^2-2x-1\right)^3+\left(2x-1\right)^3=\left(x^2-x+1\right)^3+\left(x^2+x-3\right)^3\)
\(\Leftrightarrow\left(2x^2-2x-1\right)^3+\left(2x-1\right)^3+\left(x-x^2-1\right)^3=\left(x^2+x-3\right)^3\)
\(2x^2-2x-1=a;2x-1=b;x-x^2-1=c\)
\(\Leftrightarrow a+b=2x^2-2;b+c=3x-x^2-2;c+a=x^2-x-2;a+b+c=x^2+x+3\)
\(\Leftrightarrow a^3+b^3+c^3=\left(a+b+c\right)^3\)
\(\Rightarrow3\left(a+b\right)\left(b+c\right)\left(c+a\right)=0\)
\(\Rightarrow a+b=0;b+c=0;c+a=0\Rightarrow2x^2-2=0;3x-x^2-2=0\Rightarrow x\in\left\{-1;1;2\right\};x^2-x=0\)