Ta có : \(\frac{2-x}{2004}-1=\frac{1-x}{2005}-\frac{x}{2006}\)
\(\Leftrightarrow\frac{2-x}{2004}+1=\frac{1-x}{2005}+1-\frac{x}{2006}+1\)
\(\Leftrightarrow\frac{2-x}{2004}+\frac{2004}{2004}=\frac{1-x}{2005}+\frac{2005}{2005}-\frac{x}{2006}+\frac{2006}{2006}\)
\(\Leftrightarrow\frac{2006-x}{2004}=\frac{2006-x}{2005}+\frac{2006-x}{2006}\)
\(\Leftrightarrow\left(2006-x\right)\left(\frac{1}{2004}-\frac{1}{2005}-\frac{1}{2006}\right)=0\)
\(\Leftrightarrow x-2006=0\)
\(\Rightarrow x=2006\)
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