Question

giải hộ mình với

(x-2)(x-3)=(x-2)(x+1)

Answer 1

\(\left(x-2\right)\left(x-3\right)=\left(x-2\right)\left(x+1\right)\)

\(\Leftrightarrow x^2-5x+6=x^2-x-2\)

\(\Leftrightarrow-4x+8=0\)

\(\Leftrightarrow x=2\)

Vậy ...

Answer 2

(x-2)(x-3)=(x-2)(x+1)

\(x^2-5x+6=x^2-x-2\)

\(x^2-x^2-5x+x=-6-2\)

\(-4x=-8\)

\(x=2\)

\(\text{Vậy x=2}\)