a) =\(\dfrac{21}{35}+\dfrac{10}{35}+\dfrac{4}{35}=\dfrac{21+10+4}{35}=\dfrac{35}{35}=1\)
b) =\(\dfrac{16}{24}+\dfrac{15}{24}-\dfrac{12}{24}=\dfrac{19}{24}\)
c) =\(\dfrac{35}{40}+\dfrac{80}{40}-\dfrac{24}{40}+\dfrac{120}{40}=\dfrac{35+80-24+120}{40}=\dfrac{211}{40}\)