Question

giải hệ pt: xy=120
xy=(x+10)(y-1)

Answer 1

\(\left\{{}\begin{matrix}xy=120\\xy=\left(x+10\right)\left(y-1\right)\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}xy=120\\xy=xy-x+10y-10\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}xy=120\\x=10y-10\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}\left(10y-10\right)y=120\\x=10y-10\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}y^2-y-12=0\\x=10y-10\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}y=4\Rightarrow x=30\\y=-3\Rightarrow x=-40\end{matrix}\right.\)