\(\Leftrightarrow\int^{2x-3\sqrt{2}y=\sqrt{2}}_{2x+y\sqrt{2}=-2}\Leftrightarrow\int^{4\sqrt{2}y=-\sqrt{2}\left(\sqrt{2}+1\right)}_{2x=-2-y\sqrt{2}}\Leftrightarrow\int^{y=-\frac{\sqrt{2}+1}{4}}_{2x=-2+\frac{\sqrt{2}\left(\sqrt{2}+1\right)}{4}}\Leftrightarrow\int^{y=-\frac{\sqrt{2}+1}{4}}_{x=\frac{\sqrt{2}-6}{2}}\)